2z^2+2z+1-2i=0

Solution for 2z^2+2z+1-2i=0 equation:

Simplifying
2z2 + 2z + 1 + -2i = 0

Reorder the terms:
1 + -2i + 2z + 2z2 = 0

Solving
1 + -2i + 2z + 2z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -2i + 2z + -1 + 2z2 = 0 + -1

Reorder the terms:
1 + -1 + -2i + 2z + 2z2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2i + 2z + 2z2 = 0 + -1
-2i + 2z + 2z2 = 0 + -1

Combine like terms: 0 + -1 = -1
-2i + 2z + 2z2 = -1

Add '-2z' to each side of the equation.
-2i + 2z + -2z + 2z2 = -1 + -2z

Combine like terms: 2z + -2z = 0
-2i + 0 + 2z2 = -1 + -2z
-2i + 2z2 = -1 + -2z

Add '-2z2' to each side of the equation.
-2i + 2z2 + -2z2 = -1 + -2z + -2z2

Combine like terms: 2z2 + -2z2 = 0
-2i + 0 = -1 + -2z + -2z2
-2i = -1 + -2z + -2z2

Divide each side by '-2'.
i = 0.5 + z + z2

Simplifying
i = 0.5 + z + z2